OpenStack floating IP convenience
Problem: I am working in a tenant which has a couple of hosts with floating IPs assigned. I always have to look them up either manually using the command line clients (and dealing with all those UUIDs), or manually in the web GUI. Didn’t like.
Solution: Python script, which outputs FLOATING_IP -> HOST_NAME.
Here it is.
#!/usr/bin/env python
from novaclient import client
import novaclient.v2.floating_ips as os_fips
import novaclient.v2.servers as os_servers
import novaclient.v2.networks as os_networks
#from pprint import pprint as pp
import os
from sys import exit
def error(printme):
print("ERROR: {}".format(printme))
exit(-1)
def check_env():
for a in ("OS_TENANT_ID", "OS_TENANT_NAME", "OS_AUTH_URL", "OS_USERNAME", "OS_PASSWORD"):
if not os.environ.get(a): error("Please set ${}".format(a))
def get_client():
check_env()
return client.Client(2,
os.environ["OS_USERNAME"],
os.environ["OS_PASSWORD"],
os.environ["OS_TENANT_NAME"],
os.environ["OS_AUTH_URL"])
if __name__=="__main__":
nova = get_client()
fipman = os_fips.FloatingIPManager(nova)
servman = os_servers.ServerManager(nova)
netman = os_networks.NetworkManager(nova)
ips = fipman.list()
srs = servman.list()
id2server = {}
for a in srs:
id2server[a.id] = a
ips = [(ip.ip, ip.instance_id) for ip in ips]
# filter out unused floating ips (which have as instance id)
ips = filter(lambda x: x[1], ips)
# create (IP, SERVER_NAME pairs)
ips = map(lambda x: (x[0], id2server[x[1]].name), ips)
# sort for convenience by host instance name
ips = sorted(ips, key=lambda x: x[1].lower())
for a in ips:
print("{:18s} {}".format(a[0], a[1]))
Sample output:
$ tools/list_ips
10.64.108.163 ab_1695_1_dml
10.64.108.199 ab_1695_1_jump
10.64.108.160 media0
10.64.109.97 RJD1_CouchbaseA1
10.64.109.99 RJD1_JumpServer
10.64.109.98 RJD1_OpenshiftMaster
10.64.109.148 tla-centos66
Groovy.
Main sources: